-2s^2-9s+3=0

Solution for -2s^2-9s+3=0 equation:

-2s^2-9s+3=0

a = -2; b = -9; c = +3;
Δ = b2-4ac
Δ = -92-4·(-2)·3
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*-2}=\frac{9-\sqrt{105}}{-4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*-2}=\frac{9+\sqrt{105}}{-4}
$